From Cambridge to Eternity: “Dimension Algebra 04”
<Questions for
Review of “Money Demand”>
1. What
was “money” historically?
-
Commodities: shells, stones, copper, nickel, silver, gold and so on
-
Classical economists: a veil
-
David Hume among others 3): the annual average 2) of
monetary outstanding
-
John M. Keynes among others: the outstanding balance as at a moment of interest
- John R. Hicks among others 4): something that is a “constant” fraction (or multiple) of the annual “nominal” income: i.e. M= k∙I = k∙( P∙Y)
2. How do we calculate the average?
<A>
There are indefinitely many. For more, please refer to:
3. What
is the quantity “equation” M∙V= P∙Y
meant with?
<A> First of all, the name might well be corrected because it is not exactly an equation but a “definition identity” which must always and everywhere hold true.
Suppose a tiny economy “Yap” in the steady
state with a purchasing party on one side and a retailing party on the other side of the market. For the sake
of convenience, we assume that the money of the retailing party (as the collective
employer) recycles to the purchasing party (as the collective employee) when
the latter’s hands are empty. For simplicity, we put on hold all the trade in
intermediate goods, old assets and anything else other than the final goods,
services and assets which are created in the year and only in that year. In addition,
we choose the most popular way of averaging. 2)
We take, for example, in Yap: 600 stones current as money legally valued one ducat each (M); trade worth 4,800 ducats (P∙Y) taking place over the year in a nicely-differentiable distribution. Then, the average money balance of the spending (demanding) party is a half (1/2) of the initial balance.
Accounting for the Yapean economy:
- The monetary balance outstanding: M= 600 ducats all through the year
-The nominal GDP P∙Y= 4,800 ducats
per annum
- The economy-wide velocity of money V= 4,800/ 600= 8 turns per annum
- The average
liquidity preference of the spending party Mp= (1/ 2)∙M=
300 ducats
- The “constant” of the Cambridge Quantity equation k= 300 ducats/ (4,800 ducats per year) = (1/ 2)∙(1/ 8 turns per year)= 0.0625 year = 22.5 days.
“Yep,
k is a ‘constant’ in Yap, either 0.0625 year
or 22.5 days.”
(Q.E.D.)
4. What
in the reality will the individual “constant” k of John R. Hicks be?
<A>Please
come back to yesterday.
5. Would
there be any realistic way to come up with an estimate of the “constant” k as for the national economy of modern
times?
<A>
We would not know until the end of time if in Here save Yap.
Comments
Post a Comment